There are (25) Comments for the Domain of a function
NorwegianNightmare88 says...
how do you write so good with a mouse on the computer?!?!?!?!?
Posted on: 19/Nov/2009@1:17 am
Mejiera12 says...
I think 8bit nice one catching that
Posted on: 21/Nov/2009@4:31 pm
limon914 says...
Very helpful, thanks!
Posted on: 24/Nov/2009@5:34 pm
Archer6633 says...
If it only was recorded by a camera.. you would rock..!
Posted on: 25/Nov/2009@9:40 pm
mack520 says...
I think hey mon- where do we send money? Paypal?
Posted on: 29/Nov/2009@5:00 am
VFCfuturelove1 says...
I think crap I CANT FIND WUT I WANT!!.. so my homework goes a little like this ..Find the range(dependent),R, of every funcion given the domain (independent),D.then here’s #9-f(x)=x(cubed)+3 then to the side D={-3,0,3}..HELP?!?!=[..don't get it..i have 2 turn this in 2morrow..will make sure 2 pay attention in class latr..bt for now HELP PLEASE!!=]
Posted on: 1/Dec/2009@1:43 pm
jokersnkings says...
hey i have a problem that i reely dont get…..f{x} = kx/3x+5, x does not equal negative 5/3 and f{f{x}} =x satifies f{x} for all real vaulues of x expect negative 5/3 what is the value of k
Posted on: 2/Dec/2009@4:58 pm
sblackstone says...
What I would like to know is why this is the first result when you search for ‘funions’ on youtube.
Posted on: 5/Dec/2009@11:05 pm
forensicsbound says...
hey thanks….just outta curiosity, do you have a vid like this on finding range or can you direct me 2 a video on this. Thanks!
Posted on: 6/Dec/2009@4:51 am
chevelledude888 says...
this is scary if u read this this far u will die in 10 days if u dont send to any 15 videos in 2 hours SORRY x .
Posted on: 8/Dec/2009@1:04 pm
exquibble says...
I think in the last example 1/2 is not an even or odd number but it is a real number. Your domain in this example is wrong.
Posted on: 10/Dec/2009@6:36 pm
8bit2008 says...
I think Forgive me if I’m wrong, but on that last question, isn’t the domain the set of all INTEGERS such that x is not equal to 1?
Posted on: 12/Dec/2009@11:48 am
dotageek11 says...
I think can you find domain and range of y=2x^2-x? thanks a lot.
Posted on: 15/Dec/2009@5:29 pm
majorkeybaree says...
absolute value?
Posted on: 16/Dec/2009@6:18 pm
abedbae says...
The last problem was tricky! almost got me
Posted on: 17/Dec/2009@12:01 am
abedbae says...
I think thanks!
Posted on: 18/Dec/2009@3:32 am
buzwazfuz says...
thank you, you always get me through my math and physics homework. thx agian
Posted on: 19/Dec/2009@8:28 am
jensennn93 says...
thank you sooooo much!
Posted on: 20/Dec/2009@5:36 am
sarafann says...
I think ty, saved my grade
Posted on: 20/Dec/2009@6:53 pm
RoseDelion says...
I can’t stand my math teacher, he didn’t teach us this, he just gives us paper, does 1 example. And expects us to get an A+
I need help on how to graph dilations/translations
Thanks your very helpful =)
Posted on: 21/Dec/2009@10:39 pm
DCaple0013 says...
u have a lot of time to be doing this. thank you tho for real i got this take home quiz and ive been falling behind. good man u r. peace.
Posted on: 23/Dec/2009@12:39 pm
macardent says...
YOU ARE AWESOME! Now I can hope I get perfect in tomorrows test!
Posted on: 25/Dec/2009@12:54 am
khanacademy says...
I think for y=x^2, y is a function of x or y=f(x)=x^2 because if you input any x into the f(x)=x^2, you get a unique value. For x=y^2, x is a function of y for the same reason (x=f(y)=y^2) but y is not a function of x. For x=y^2, if x=4, then y could be +2 or -2 so you don’t get a unique y.
Posted on: 25/Dec/2009@12:21 pm
levimariah says...
Sal; can you help me understand how to determine if a relation is a function or not, like y=x^2 vs. x=y^2 one is a function and one is not,i’m haveing a hard time deciphering the info. also; could f(x) be considered y when x is in the relation? thanks, Tim
Posted on: 27/Dec/2009@4:57 am
payasitopimpim2002 says...
instructive useful …..awesome…thanks my friend…………
how do you write so good with a mouse on the computer?!?!?!?!?
I think 8bit nice one catching that
Very helpful, thanks!
If it only was recorded by a camera.. you would rock..!
I think hey mon- where do we send money? Paypal?
I think crap I CANT FIND WUT I WANT!!.. so my homework goes a little like this ..Find the range(dependent),R, of every funcion given the domain (independent),D.then here’s #9-f(x)=x(cubed)+3 then to the side D={-3,0,3}..HELP?!?!=[..don't get it..i have 2 turn this in 2morrow..will make sure 2 pay attention in class latr..bt for now HELP PLEASE!!=]
hey i have a problem that i reely dont get…..f{x} = kx/3x+5, x does not equal negative 5/3 and f{f{x}} =x satifies f{x} for all real vaulues of x expect negative 5/3 what is the value of k
What I would like to know is why this is the first result when you search for ‘funions’ on youtube.
hey thanks….just outta curiosity, do you have a vid like this on finding range or can you direct me 2 a video on this. Thanks!
this is scary if u read this this far u will die in 10 days if u dont send to any 15 videos in 2 hours SORRY x .
I think in the last example 1/2 is not an even or odd number but it is a real number. Your domain in this example is wrong.
I think Forgive me if I’m wrong, but on that last question, isn’t the domain the set of all INTEGERS such that x is not equal to 1?
I think can you find domain and range of y=2x^2-x? thanks a lot.
absolute value?
The last problem was tricky! almost got me
I think thanks!
thank you, you always get me through my math and physics homework. thx agian
thank you sooooo much!
I think ty, saved my grade
I can’t stand my math teacher, he didn’t teach us this, he just gives us paper, does 1 example. And expects us to get an A+
I need help on how to graph dilations/translations
Thanks your very helpful =)
u have a lot of time to be doing this. thank you tho for real i got this take home quiz and ive been falling behind. good man u r. peace.
YOU ARE AWESOME! Now I can hope I get perfect in tomorrows test!
I think for y=x^2, y is a function of x or y=f(x)=x^2 because if you input any x into the f(x)=x^2, you get a unique value. For x=y^2, x is a function of y for the same reason (x=f(y)=y^2) but y is not a function of x. For x=y^2, if x=4, then y could be +2 or -2 so you don’t get a unique y.
Sal; can you help me understand how to determine if a relation is a function or not, like y=x^2 vs. x=y^2 one is a function and one is not,i’m haveing a hard time deciphering the info. also; could f(x) be considered y when x is in the relation? thanks, Tim
instructive useful …..awesome…thanks my friend…………